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Randomized multiple-choice question with dynamic drawing

A cannon ball with mass $m =1.4\rm\ kg$ is fired downward from a cliff at a height $h = 8.193\rm\ m$, at an angle $\theta = 33^o$ with respect to the horizontal, and an initial velocity $v_0 = 23 \rm\ m/s$, as illustrated in the figure below.

Suppose the ball hits the ground after $t = 0.54\rm\ s$. What is the distance from the base of the cliff that the ball hits the ground? Assume the acceleration due to gravity is $g=9.8 \rm\ m/s^2$.

Correct answer

  • (c) $d = 10.416\rm\ m$

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Randomized multiple-choice question with dynamic drawing

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Started at:
2026-09-19 10:08:17 (CDT)
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{
  "t": {
    "key": "c",
    "html": "$d = 10.416\\rm\\ m$",
    "score": 1,
    "feedback": null
  }
}
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dec frac
rad deg